Machine-translated by Google. Questions are authored in English.
Top

Discussion

That machine's mechanical output power is

  • A.1 kW
  • B.21 kW
  • C.19 kW
  • D.20 kW

Answer: C

Correct answer: 19 kW

The mechanical power is what is left of the air gap power after the rotor copper loss:

\[ P_{mech} = (1-s)P_g = 0.95 \times 20 = 19 \text{ kW} \]

The shaft output is a little less again, by the friction and windage. Note that the rotor efficiency here is 95 per cent, equal to \( 1-s \), which is the ceiling any scheme controlling speed by slip must live under.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.