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A machine whose direct-on-line starting current is 300 A is started star-delta. The line current at starting becomes

  • A.33 A
  • B.300 A
  • C.100 A
  • D.173 A

Answer: C

Correct answer: 100 A

Star-delta starting reduces the line current to one third of the direct-on-line value:

\[ I = \frac{300}{3} = 100 \text{ A} \]

The 173 A figure would be \( 300/\sqrt{3} \), which accounts for the winding voltage reduction but forgets that the line and phase currents are also related differently in the two connections.

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