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 STATEMENT :

D > A ≥ M ≤ N ; M ≥ E < L

CONCLUSION I : D > E

CONCLUSION II : N ≤ A

CONCLUSION III : A ≥ L

CONCLUSION IV : L < D

  • A.Only III is true
  • B.Only I is true
  • C.Only II is true
  • D.None is true
  • E.Only I and IV are true

Answer: B

Correct answer: Only I is true

The statements give \( D > A \ge M \le N \) and \( M \ge E < L \). M is the pivot: the first chain descends to it from D and then rises to N, and the second descends from it to E and then rises to L. Anything that has to cross M from one branch to another is therefore undecidable.

I. \( D > E \): here the run does not cross a reversal - \( D > A \ge M \ge E \) descends throughout, and the first link is strict. True.

II. \( N \le A \): both N and A stand above M on different branches, so their order is free. With \( M = 1 \), \( A = 2, N = 9 \) and \( A = 9, N = 2 \) both satisfy every statement. Not determined.

III. \( A \ge L \): L stands above E and A stands above M, and the two are joined only through the reversal at E. Not determined.

IV. \( L < D \): the same obstacle - L is reached only by climbing back up from E, so nothing caps it. Not determined.

Only I follows.

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