Discussion
Statements: B<P; P≤S; S=M; M≥F; Q≥M; M<O
Conclusions:
i. P≤F
ii. B<Q
iii. Q≥M
iv. F<O
Answer: C
Correct answer: Only II,III and IV are true
The statements give \( B < P \le S = M \), with \( M \ge F \), \( Q \ge M \) and \( M < O \). Since \( S = M \) the two can be merged, leaving M as the hub that everything else attaches to: B and P climb up to it, F hangs below it, and Q and O stand above it.
ii. \( B < Q \): the run \( B < P \le S = M \le Q \) points one way throughout and opens strict. True.
iii. \( Q \ge M \): this is one of the statements restated, which is always worth checking for - a conclusion that merely repeats a premise is true by definition. True.
iv. \( F < O \): \( F \le M < O \), strict at the second link. True.
i. \( P \le F \): P and F both sit at or below M on different branches, so nothing orders them. With \( M = 10 \), \( P = 9, F = 1 \) and \( P = 1, F = 9 \) are equally allowed. Not determined.
So ii, iii and iv follow and i does not.
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