Discussion
Statements: A ≥ B; F < E; A ≤ D; F ≤ B;C = B
Conclusions:
I. C < E
II. D ≥ B
III.A ≥ F
IV.E > D
Answer: D
Correct answer: II and III are true
The statements give \( F \le B \le A \le D \), with \( C = B \) and \( F < E \).
II. \( D \ge B \): the chain \( B \le A \le D \) reads straight off. True.
III. \( A \ge F \): likewise from \( F \le B \le A \). True.
I. \( C < E \): E enters only through \( F < E \), and C equals B, which stands above F. So C and E both lie above F on separate branches and are not ordered by it. With \( F = 1 \), \( C = 2, E = 9 \) and \( C = 9, E = 2 \) both work. Not determined.
IV. \( E > D \): the same obstacle, further along - D is at the top of the first chain and E is on the branch above F, with nothing joining them. Not determined.
II and III follow. The lesson is that \( F < E \) is a dead end: F is the bottom of the main chain, so anything hanging above F is left free.
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