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Statements: P=M; Q≤R; T>Q; M<R
Conclusions:
I. M < R
II. R > T
III. P > T
IV. P > Q

  • A.None is true
  • B.Only I is true
  • C.Only I and II are true
  • D.Only II and III are true
  • E.Only IV is true

Answer: B

Correct answer: Only I is true

The statements give \( P = M \), \( Q \le R \), \( T > Q \) and \( M < R \). R is the high point: M and Q both sit below it, and T is tied only to Q from above.

I. \( M < R \): this is one of the statements repeated verbatim. True.

II. \( R > T \): both R and T stand above Q, so their order is free. With \( Q = 1 \), take \( R = 2, T = 9 \) or \( R = 9, T = 2 \). Not determined.

III. \( P > T \): P equals M, which sits below R; T sits above Q. No chain runs between them. Not determined.

IV. \( P > Q \): P and Q both sit below R on separate branches - the mirror image of the II case. Not determined.

Only I follows. Three of the four conclusions fail for the same structural reason: two elements attached to a common third from the same side are never ordered by that attachment.

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