Discussion
Statements: A $ M, P @ L, K # P, A $ L
Conclusions:
I. K # L
II. A @ P
III.L*A
IV.M # P
Answer: D
Correct answer: Only III is true
This set’s code reads: \(\$\) is “not smaller than”, so \(\ge\); \(@\) is “neither smaller nor equal”, so \(>\); \(\#\) is “neither greater nor equal”, so \(<\); \(\&\) is \(=\); and \(*\) is “not greater than”, so \(\le\). The statements become \( A \ge M \), \( P > L \), \( K < P \) and \( A \ge L \).
III. \( L \le A \) is the fourth statement read the other way round: \( A \ge L \) is precisely \( L \le A \). True.
I. \( K < L \): K and L both sit below P, so nothing orders them. Not determined.
II. \( A > P \): A and P are connected only through L, which both stand above - \( A \ge L \) and \( P > L \). Not determined.
IV. \( M < P \): M hangs below A, and A is itself unordered against P, so M is further adrift still. Not determined.
Only III follows - and it follows for the simplest possible reason, being a statement restated. Checking each conclusion against the statements for an exact restatement before reasoning about chains often saves the work.
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