Discussion
Statements: S > O ≥ U ≥ P; O ≤ T < R; T ≥ E > A
Conclusions:
I. T > P
II. T = P
Answer: C
Correct answer: Either Conclusion I or II is true.
The statements are \( S > O \ge U \ge P \), \( O \le T < R \) and \( T \ge E > A \).
Both conclusions compare T with P, so assemble that run first: \( T \ge O \ge U \ge P \). Every link is weak, so the most that can be said is \[ T \ge P. \]
I claims \( T > P \) and II claims \( T = P \). Neither is forced - taking all four of T, O, U and P equal satisfies the statements and makes II true, while \( T = 10, O = 5, U = 3, P = 1 \) makes I true. But \( T \ge P \) leaves exactly these two possibilities and no third, so one of them must hold.
That is the “either…or” case: the two conclusions form a complementary pair spanning everything the statements allow. The signature to watch for is a chain of purely weak links between the two elements named - one strict link anywhere in it would have settled the matter and made I definitely true.
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