Discussion
Statements: G < R = A ≤ S; R > T
Conclusion:
I. G < S
II. S > T
Answer: D
Correct answer: Both conclusions I and conclusion II are true.
The statements give \( G < R \), \( R = A \), \( A \le S \) and \( R > T \).
Conclusion I claims \( G < S \). Chain it: \( G < R = A \le S \). The strict link at the left end carries through the equality and the weak link, giving \( G < S \). True.
Conclusion II claims \( S > T \). Chain it the other way: \( S \ge A = R > T \). Again a single strict link makes the whole relation strict, so \( S > T \). True.
Both follow, so the answer is that both conclusions are true. Note how R does the work in each case - it is the element every other one is tied to, and finding that pivot is usually the quickest route through a question of this shape. The statements in this record had been destroyed by a stray < in the stored HTML; they are restored above from the relations the surviving working refers to.
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