Discussion
Statements: W # H π I % C $ H © S
Conclusion:
I. C $ W
II. C © S
Answer: B
Correct answer: both conclusions I and II are true.
This set’s code reads \(\#\) as “smaller than”, \(©\) as “greater than”, \(\pi\) as \(\le\), \(\$\) as \(\ge\), and \(\%\) as “neither smaller nor greater”, that is \(=\). The statement becomes \[ W < H \le I = C \ge H > S. \] Note that H is named twice, which is what ties the two halves together.
I. \( C \ge W \): the run \( W < H \le I = C \) points one way throughout and opens strict, so \( C > W \) - which certainly satisfies the weaker \( C \ge W \) that the conclusion states. True.
II. \( C > S \): reading from C, \( C \ge H > S \), strict at the last link. True.
Both follow. Conclusion I is the one candidates most often reject, on the grounds that the chain gives a strict relation while the conclusion asks for a weak one; but \( \ge \) requires only that C is not smaller than W, and \( C > W \) delivers that. A strict result always satisfies the corresponding weak claim - never the reverse.
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