Discussion
Statements: A # N % O π T π H # E
Conclusion:
I. E $ O
II. H © N
Answer: D
Correct answer: only conclusion I is true.
This set’s code reads \(\#\) as \(<\), \(©\) as \(>\), \(\pi\) as \(\le\), \(\$\) as \(\ge\) and \(\%\) as \(=\). The statement becomes \[ A < N = O \le T \le H < E. \] This one has no reversal at all - it climbs from A to E in a single direction - so every comparison along it can be settled, and the only question is whether the result is strict.
I. \( E \ge O \): the run \( O \le T \le H < E \) contains a strict link at the end, so in fact \( E > O \), which satisfies the weaker claim the conclusion makes. True.
II. \( H > N \): the run \( N = O \le T \le H \) is weak at every link, so it gives only \( H \ge N \). The conclusion asks for the strict relation, and equality is not excluded - taking N, O, T and H all equal satisfies every statement. Not determined.
Only I follows. The contrast between the two is the whole lesson: a chain with one strict link proves the strict conclusion and the weak one; a chain of purely weak links proves only the weak one.
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