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Which of the following expressions has E>G and C>F definitely true?

  • A.A < E ≥ B > D > F = G < C
  • B.B ≤ A < C < D > E > F > G
  • C.A ≤ C ≥ B ≥ D < G ≥ E > F
  • D.D ≤ G > E ≥ F > C ≤ A ≤ B
  • E.C ≥ A > D ≥ B ≥ E = G > F

Answer: A

Correct answer: A < E ≥ B > D > F = G < C

Reading this option, E ≥ B > D > F = G gives E > G, and G < C with G = F gives C > F. Both required relations therefore follow from unbroken chains. Each of the other options breaks at least one of them at a reversal of direction.

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