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At Mach 2.0, the same relation \( (1 + 0.2M^2)^{3.5} \) gives a total to static pressure ratio of approximately

  • A.3.50
  • B.2.00
  • C.7.82
  • D.1.60

Answer: C

Substituting gives \( 1.8^{3.5} \approx 7.82 \). Comparing this with the 1.6 available at Mach 0.85 shows how completely ram compression dominates at high speed, and why a ramjet needs no compressor at all in that regime.

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