Discussion
What will be the output of the following statement ?
int a = 10; printf("%d &i", a,10);Answer: D
The output is 10 &i, so the answer is None of the above.
The format string "%d &i" contains only one conversion specifier, %d, which prints the value of a, 10. The rest, a space followed by the characters &i, is ordinary text and is printed as it stands. The extra argument 10 has no specifier to use it and is ignored; C allows surplus arguments to printf.
'10 10' would be the output of "%d %i"; with & instead of % the second number is never printed. The statement compiles, so it is not an error.
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