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In the following figure, the value of x will be :

Three circles, each split into four quarters with a number in the centre: 15, 17, 9, 8 around 40; 6, 2, 3, 12 around 28; 23, 28, 13, 4 around x

  • A.1
  • B.8
  • C.12
  • D.27

Answer: A

The value of x is 1.

In each circle, the product of the two lower numbers minus the sum of the two upper numbers gives the centre:

\[ \begin{aligned} 9 \times 8 - (15 + 17) &= 72 - 32 = 40 \\ 3 \times 12 - (6 + 2) &= 36 - 8 = 28 \\ 13 \times 4 - (23 + 28) &= 52 - 51 = 1 \end{aligned} \]

The rule fits both known circles, so x = 1. The other options (8, 12, 27) do not satisfy any rule that also produces 40 and 28 in the first two circles.

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