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Two instruments of 5 VA and 10 VA at 5 A are connected in series on one current transformer, together with leads of 0.1 \( \Omega \). The total burden is

  • A.15 VA
  • B.15.1 VA
  • C.22.5 VA
  • D.17.5 VA

Answer: D

Correct answer: 17.5 VA

The instruments add directly, and the leads must be converted from ohms at the rated current: \[ 5 + 10 + (0.1 \times 5^{2}) = 5 + 10 + 2.5 = 17.5\ \mathrm{VA}. \] The 15.1 offered adds the lead resistance as though ohms were volt-amperes, and the 15 ignores the leads altogether - which is exactly the mistake that overburdens a current transformer in the field.

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