Discussion
The mean value of \( f \) over \( [a,b] \) is
Answer: A
The mean is the total divided by the length of the interval, so that a constant function returns its own value:
\[ \bar{f} \;=\; \frac{1}{b-a}\int_{a}^{b} f(x)\,dx. \]
Averaging the endpoint values ignores everything between them, and the integral of \( f^{2} \) leads to the root-mean-square instead, which needs a square root as well
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