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Estimating that same \( \displaystyle\int_{0}^{2} x^{2}dx \) by Simpson's one-third rule with two strips gives

  • A.\( 3 \), the same as the trapezoidal estimate
  • B.\( 4 \), twice the exact value
  • C.\( 2 \), below the exact value
  • D.\( 8/3 \), the exact value

Answer: D

With the same ordinates and \( h = 1 \),

\[ I \;\approx\; \frac{1}{3}\left[0 + 4(1) + 4\right] \;=\; \frac{8}{3}. \]

Simpson's rule fits a parabola, and the integrand *is* a parabola, so the fit is exact. The rule is in fact exact for any cubic as well, which is why its error term involves the fourth derivative

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