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Estimating \( \displaystyle\int_{0}^{1}\frac{dx}{1+x} \) by Simpson's one-third rule with two strips gives about

  • A.\( 0.6931 \)
  • B.\( 0.6944 \)
  • C.\( 0.7500 \)
  • D.\( 0.6667 \)

Answer: B

With \( h = 0.5 \) the ordinates are \( 1 \), \( 1/1.5 = 0.6667 \) and \( 0.5 \), so

\[ I \;\approx\; \frac{0.5}{3}\left[1 + 4(0.6667) + 0.5\right] \;=\; \frac{0.5}{3}(4.1667) \;=\; 0.6944. \]

The exact value is \( \ln 2 = 0.6931 \), so two strips already give three-figure accuracy, which is why the rule is preferred to the trapezoidal one

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