Discussion
A sensor produces a 4-byte sample every 2 ms and the consuming task runs every 50 ms. The queue must hold at least
Answer: C
Correct answer: 25 samples
\[ \frac{50\ \mathrm{ms}}{2\ \mathrm{ms}} = 25\ \mathrm{samples}. \] That is the minimum, and a real design would add margin for jitter in the consumer’s scheduling. Sizing to the exact figure leaves nothing for the case where the task runs a little late.
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