Discussion
A task must wait for either a message or a 100 ms timeout, whichever comes first. This is done by
Answer: D
Correct answer: a queue receive with a 100 ms timeout
The kernel primitive already does exactly this: it returns when a message arrives or when the timeout expires, whichever is first, and reports which happened. Polling in a loop wastes processor time and adds latency, and a second task or a mutex timeout solves a different problem.
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