Discussion
A gamma-ray of 3.43 MeV energy undergoes pair production. The electron and positron formed move with equal kinetic energy in opposite direction to each other. The kinetic energy of the positron is nearly :
Answer: C
The positron's kinetic energy is nearly 1.20 MeV.
Creating the pair uses \(2m_{e}c^{2} = 1.022\) MeV; the rest is shared equally as kinetic energy:
\[ \begin{aligned} K &= \frac{3.43 - 1.022}{2} \\ &= \frac{2.408}{2} \approx 1.20\ \text{MeV} \end{aligned} \]
The option 1.022 MeV is the threshold energy itself, and 0.511 MeV is the rest energy of one particle; neither is a kinetic energy here.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development