Discussion
A single-phase full wave voltage source inverter has a resistive load of \(R = 2.4\ \Omega\) and the DC input voltage is 100 V. What is the RMS output voltage at the fundamental frequency?
Answer: C
The output of a single phase full bridge (full wave) voltage source inverter is a square wave of amplitude \(\pm V_{dc}\). Its Fourier series has the fundamental component with peak value \(4V_{dc}/\pi\), so the RMS value of the fundamental is
\[ \begin{aligned} V_{1} = \frac{4V_{dc}}{\pi\sqrt{2}} = 0.9\,V_{dc} \\ &= 0.9 \times 100 = 90\ \text{V} \end{aligned} \]
The value 100 V is the RMS value of the whole square wave (it includes the harmonics), not the fundamental. The load resistance is not needed for the voltage. The answer is 90 V, option C.
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