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You have the following routing table. Which of the following networks will not be placed in the neighbor routing table?

R    192.168.30.0/24 [120/1] via 192.168.40.1, 00:00:12, Serial0
C    192.168.40.0/24 is directly connected, Serial0
     172.16.0.0/24 is subnetted, 1 subnets
C    172.16.30.0 is directly connected, Loopback0
R    192.168.20.0/24 [120/1] via 192.168.40.1, 00:00:12, Serial0
R    10.0.0.0/8 [120/15] via 192.168.40.1, 00:00:07, Serial0
C    192.168.50.0/24 is directly connected, Ethernet0

  • A.172.16.30.0
  • B.192.168.30.0
  • C.10.0.0.0
  • D.All of them will be placed in the neighbor routing table.

Answer: C

Correct answer: 10.0.0.0

The 10.0.0.0/8 route already has a metric of 15, and RIP adds one hop when advertising it onward, giving 16 - which RIP defines as infinity, meaning unreachable. The neighbour therefore discards it. The other entries have metrics of 0 or 1 and will be advertised and installed normally.

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