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What will be the output of the program?

public class Listing29
{
    Listing29()
    {
        double up = 1.0 / 0;
        double down = -1.0 / 0;
        System.out.println(up + " " + down);
    }

    public static void main(String[] args)
    {
        new Listing29();
    }
}

  • A.Infinity -Infinity
  • B.NaN NaN
  • C.An ArithmeticException is thrown.
  • D.The program prints 0.0 -0.0

Answer: A

Dividing a non-zero double by zero gives a signed infinity rather than throwing, because the floating-point types have values for it. Only zero over zero is indeterminate and gives NaN. The same expressions with int operands would throw ArithmeticException.

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