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Three connected railway coaches A, B and C of masses \(m_{A}\), \(m_{B}\) and \(m_{C}\), respectively are being pulled by a locomotive with force F over a horizontal track. The coaches may be assumed to move on frictionless wheels with negligible air resistance. The tension in the connector between coaches A and B is

Railway coaches coupled in the order C, B, A with force F pulling coach A forward

  • A.F
  • B.\(Fm_{A}/(m_{A} + m_{B} + m_{C})\)
  • C.\(Fm_{B}/(m_{A} + m_{B} + m_{C})\)
  • D.\(F(m_{B} + m_{C})/(m_{A} + m_{B} + m_{C})\)

Answer: D

The tension between A and B is \(F(m_{B} + m_{C})/(m_{A} + m_{B} + m_{C})\).

The whole train accelerates together at

\[ a = \frac{F}{m_{A} + m_{B} + m_{C}} \]

The coupling between A and B is the only horizontal force on the rear part of the train, coaches B and C together, so it must give them this acceleration:

\[ \begin{aligned} T_{AB} &= (m_{B} + m_{C})a \\ &= \frac{F(m_{B} + m_{C})}{m_{A} + m_{B} + m_{C}} \end{aligned} \]

F would be the tension only if B and C were massless. \(Fm_{A}/(\ldots)\) is the net force on A, and \(Fm_{B}/(\ldots)\) is the net force on B alone.

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