Discussion
In the given figure, find the value of current I
Answer: A
The current I is 1.7 A.
Apply Kirchhoff's current law at each junction in turn: the current flowing in equals the current flowing out.
\[ \begin{aligned} \text{first junction: } & 2 + 2 = 4\ \text{A out} \\ \text{second: } & 4 - 1 = 3\ \text{A on} \\ \text{third: } & I = 3 - 1.3 = 1.7\ \text{A} \end{aligned} \]
3.7 A adds the 1 A instead of subtracting it, 1.3 A is the other outgoing branch, and 2.7 A ignores the 1.3 A leaving the last junction.
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