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The common oxidation state of the elements of lanthanoid series is

  • A.+1
  • B.+2
  • C.+3
  • D.+4
  • E.+5

Answer: C

The common oxidation state of the lanthanoids is +3.

Lanthanoids have the configuration 4fn5d0-16s2. Losing the two 6s electrons and one 5d (or 4f) electron gives the +3 state, which is the most stable for all of them.

Some also show +2 or +4, usually when that gives an empty, half-filled or full f subshell: Eu2+ and Yb2+ (4f7, 4f14), Ce4+ (4f0). These are exceptions to the general +3, and +1 and +5 are not characteristic of the series.

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