Discussion
In CO2 Laser it is possible to obtain laser radiations at wavelengths of 9.6 \(\mu\)m and 10.6 \(\mu\)m. The energy levels corresponding to the two transitions are :
Answer: D
The transitions are (00°1) \(\rightarrow\) (02°0) and (00°1) \(\rightarrow\) (10°0).
The vibrational levels of CO\(_{2}\) are labelled (\(v_{1}v_{2}^{l}v_{3}\)) for the symmetric stretch, the bend and the asymmetric stretch. Nitrogen in the discharge excites the upper laser level, (00°1), one quantum of the asymmetric stretch. From it there are two laser transitions:
- to (10°0), the symmetric stretch: about 10.6 \(\mu\)m, the main line;
- to (02°0), the bending overtone: about 9.6 \(\mu\)m.
Option B pairs the same two transitions with the wavelengths in the opposite order to the question's (9.6 then 10.6). Options A and C describe the relaxation of the lower levels through the bending mode down to the ground state, which empties the lower level but is not the laser emission.
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