Discussion
A roll rate requirement of 0.09 helix angle at \( 90 \ \mathrm{m/s} \) on a \( 34 \ \mathrm{m} \) span demands a roll rate of
Answer: D
Rearranging gives \( p = 0.09 \times 90/17 \approx 0.476 \) radians per second, about 27 degrees per second. Larger aeroplanes need lower roll rates to meet the same helix angle, which is why the requirement is framed that way.
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