Discussion
When a person of mass m climbs up or down a rope with uniform speed \(v\) , the tension in the rope is (\(g\) = acceleration due to gravity)
Answer: A
The tension is \(mg\).
Uniform speed means zero acceleration, so the net force on the person is zero whether they move up or down. The rope must then exactly balance the weight: \(T - mg = 0\).
Expressions such as \(m(g + v)\), \(m(g - v)\) or \(mgv\) add a velocity to an acceleration, which is dimensionally wrong. The tension differs from \(mg\) only while the person is speeding up or slowing down.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development