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What will be the maximum speed of a car on a circular road of radius 12 m if the coefficient of friction between the tyres and the road is 0.3? \(g = 10 ms^{-2}\)

  • A.3.6 ms\(^{-1}\)
  • B.36 ms\(^{-1}\)
  • C.60 ms\(^{-1}\)
  • D.10 m\(^{s-1}\)
  • E.6 ms\(^{-1}\)

Answer: E

The maximum speed is 6 ms-1.

On a flat circular road, friction supplies the centripetal force. The car can go no faster than the speed at which the needed force equals the maximum friction:

\[ \begin{aligned} \frac{mv^{2}}{r} &= \mu mg \\ v &= \sqrt{\mu gr} = \sqrt{0.3 \times 10 \times 12} \\ &= \sqrt{36} = 6\ \text{m s}^{-1} \end{aligned} \]

The option 36 is \(v^{2}\), forgetting the square root, and 3.6 shifts the decimal point. The mass cancels, so the answer does not depend on the car.

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