Discussion
A passenger of mass \(m\) stands on a weighing scale in an elevator accelerating upward with an acceleration of \(\dfrac{g}{2}\) . The scale would read (\(g\) = acceleration due to gravity)
Answer: A
The scale reads \(\dfrac{3mg}{2}\).
The scale reads the normal force N on the passenger. Taking upward as positive, Newton's second law gives
\[ \begin{aligned} N - mg &= m\frac{g}{2} \\ N &= \frac{3mg}{2} \end{aligned} \]
The passenger feels heavier when the lift accelerates upward. \(\frac{mg}{2}\) is the reading for a downward acceleration of \(\frac{g}{2}\), and \(mg\) (also written \(\frac{2mg}{2}\)) is the reading at rest or at constant velocity.
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