Discussion
What will be the output of the following C code?
void main()
{
div_t res;
res = div(34, 4);
printf("quotient part = %d\n", res.quot);
printf("remainder part = %d\n", res.rem);
}
Answer: B
Correct answer: quotient part=8 remainder part=2
div(34, 4) returns a div_t structure holding both results at once: quotient 8 and remainder 2, since \(34 = 8 \times 4 + 2\). Computing both together is cheaper than a separate / and %, and the sign behaviour is guaranteed to truncate toward zero.
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