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What will be the output of the program?

#include <stdio.h>

int main()
{
    int i;
    i = scanf("%d %d", &i, &i);
    printf("%d\n", i);
    return 0;
}

 

  • A.1
  • B.2
  • C.Garbage value
  • D.Error: cannot assign scanf to variable

Answer: B

Correct answer: 2

scanf returns the number of items successfully converted and assigned, not the values themselves. Two conversions succeed here, so it returns 2, and that is what is stored in i and printed - overwriting whatever the two conversions had put there.

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