Discussion
Let \(f(x) = 10 - |x - 3|, x \in \mathbb{R}\) The maximum of \(f(x)\) occurs at
Answer: B
The maximum occurs at x = 3.
\(|x - 3| \ge 0\), with equality only at x = 3. So \(f(x) = 10 - |x - 3| \le 10\), and the largest value, 10, is reached at x = 3.
At every other option the subtracted term is positive: f(0) = 7, f(-3) = 4, f(10) = 3 and f(1) = 8. x = 10 confuses the maximum value with the point where it occurs.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development