Discussion
The distance travelled by a moving particle is given by \(s = \frac{t^{2}}{2} - 6t + 8\),where \(t\) denotes the time in seconds. The velocity becomes zero when \(t\) is equal to
Answer: D
The velocity is zero at t = 6.
Velocity is the rate of change of distance.
\[ v = \frac{ds}{dt} = t - 6 = 0 \Rightarrow t = 6\ \text{s} \]
t = 8 confuses the constant term of s with a time, and t = 3 halves the root, as if differentiating \(\frac{t^{2}}{2}\) gave \(2t\). t = 1 and t = 4 leave a non-zero velocity of -5 and -2 m/s.
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