Discussion
The vernier scale of calliper has 50 divisions which coincide with 49 main scale divisions. If each main scale division is of 0.5 mm, then the least count of the vernier is:
Answer: C
The least count is 0.01 mm.
Least count is one main scale division minus one vernier scale division. Since 50 vernier divisions equal 49 main divisions of 0.5 mm:
\[ \begin{aligned} 1\ \text{VSD} &= \frac{49 \times 0.5}{50} = 0.49\ \text{mm} \\ \text{LC} &= 0.5 - 0.49 = 0.01\ \text{mm} \end{aligned} \]
Equivalently, LC = MSD / number of vernier divisions = 0.5/50 = 0.01 mm. 0.1 mm would need only 5 vernier divisions; 1 mm and 10 mm are larger than a main scale division and cannot be a vernier's least count.
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