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The function \(\phi(x)\) satisfying the integral equation

\[ \int_{0}^{x} e^{x - \xi} \phi(\xi)\, d\xi = \frac{x^{2}}{2} \]

is

  • A.\(\frac{x^{2}}{2}\)
  • B.\(x + \frac{x^{2}}{2}\)
  • C.\(x - \frac{x^{2}}{2}\)
  • D.\(1 + \frac{x^{2}}{2}\)

Answer: C

The solution is \(\phi(x) = x - \frac{x^{2}}{2}\).

The left side is the convolution of \(e^{x}\) with \(\phi\), so take Laplace transforms:

\[ \begin{aligned} \frac{1}{s - 1}\,\Phi(s) &= \frac{1}{s^{3}} \\ \Phi(s) &= \frac{s - 1}{s^{3}} = \frac{1}{s^{2}} - \frac{1}{s^{3}} \\ \phi(x) &= x - \frac{x^{2}}{2} \end{aligned} \]

Check by differentiating the equation: \(\phi(x) + \int_{0}^{x} e^{x-\xi}\phi(\xi)\,d\xi = x\), so \(\phi(x) = x - x^{2}/2\) directly. \(x^{2}/2\) mistakes the right side for the answer, and \(x + x^{2}/2\) and \(1 + x^{2}/2\) have the wrong sign or fail at \(x = 0\), where \(\phi\) must satisfy \(\phi(0) = 0\).

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