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The problem :

Max. : \(Z = 3x_{1} + 2x_{2}\)

Subject to :

\(x_{1} - x_{2} \le 1\),
\(x_{1} + x_{2} \ge 3\)
\(x_{1}, x_{2} \ge 0\)

has :

  • A.Feasible solution
  • B.Optimum solution
  • C.Feasible but not optimum solution
  • D.Unbounded solution

Answer: D

The problem has an unbounded solution.

The feasible region is not empty: (2, 1) satisfies \(2 - 1 \le 1\) and \(2 + 1 \ge 3\). But it is not bounded. Take \(x_{1} = 0\) and let \(x_{2}\) grow: \(0 - x_{2} \le 1\) and \(0 + x_{2} \ge 3\) hold for every \(x_{2} \ge 3\), while \(Z = 2x_{2}\) increases without limit. So Z has no finite maximum.

An LP is classified by what happens to its optimum. Feasible points exist, but 'feasible solution' does not describe the outcome; 'optimum solution' and 'feasible but not optimum' do not fit either, since there is no maximum to attain. The standard classification of this problem is unbounded.

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