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For any two points \(P, Q \in \mathbb{R}^{3}\), let \(\mathit{vect}(P,Q)\) denote the vector from the point \(P\) to the point \(Q\) and let \(d(P,Q)\) denote the length of \(\mathit{vect}(P,Q)\). Let \(F: \mathbb{R}^{3} \longrightarrow \mathbb{R}^{3}\) be a linear transformation such that

\[ d(F(P), F(Q)) = d(P,Q) \]

for all \(P, Q \in \mathbb{R}^{3}\).

Which ONE of the following statements is FALSE ?

  • A.\(F\) is an injective map.
  • B.\(F\) is a surjective map.
  • C.For any four points \(P, Q, R, S\) in \(\mathbb{R}^{3}\), we have \(\mathit{vect}(F(P),F(Q)) \cdot \mathit{vect}(F(R),F(S)) =\) \(\mathit{vect}(P,Q) \cdot \mathit{vect}(R,S)\), where \(\cdot\) denotes the usual dot product in \(\mathbb{R}^{3}\).
  • D.For any four points \(P, Q, R, S\) in \(\mathbb{R}^{3}\), we have \(\mathit{vect}(F(P),F(Q)) \times \mathit{vect}(F(R),F(S)) =\) \(\mathit{vect}(P,Q) \times \mathit{vect}(R,S)\), where \(\times\) denotes the usual cross product in \(\mathbb{R}^{3}\).

Answer: D

The FALSE statement is the one about cross products.

Because \(F\) is linear, \(\mathit{vect}(F(P),F(Q)) = F(Q) - F(P) = F(Q - P)\). So the condition says \(\|F(u)\| = \|u\|\) for every vector \(u\): \(F\) is an orthogonal map, \(F^{T}F = I\).

An orthogonal map has trivial kernel, so it is injective, and an injective linear map from \(\mathbb{R}^{3}\) to itself is also surjective. By polarisation, \(u \cdot v = \frac{1}{4}(\|u + v\|^{2} - \|u - v\|^{2})\), so preserving lengths preserves dot products. Those three statements are true.

Cross products are not preserved. In general \(F(u) \times F(v) = (\det F)\,F(u \times v)\), which is not \(u \times v\). Take \(F\) the rotation by \(\frac{\pi}{2}\) about the \(z\)-axis, so \(F(e_2) = -e_1\) and \(F(e_3) = e_3\). Then \(F(e_2) \times F(e_3) = -e_1 \times e_3 = e_2\), but \(e_2 \times e_3 = e_1\).

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