Discussion
The logarithm of any number to itself as base is
Answer: C
By definition, \( \log_{a} x \) is the power to which \( a \) must be raised to give \( x \). Since
\[ a^{1} = a \]
it follows that
\[ \log_{a} a = 1 \]
for every valid base. The companion result is \( \log_{a} 1 = 0 \), since \( a^{0} = 1 \).
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