Discussion
Ln(2) is
Answer: B
The notation \( \ln \) always means the logarithm to base \( e \), so \( \ln 2 \) is a natural logarithm - the power to which \( e \) must be raised to give 2:
\[ \ln 2 \;=\; \log_e 2 \;\approx\; 0.693 \]
The trap is the numeral 2 in the bracket, which suggests base 2. The 2 is the argument, not the base. A binary logarithm is written \( \log_2 x \) and takes 2 as its base; the two are different, and indeed \( \log_2 2 = 1 \) whereas \( \ln 2 \approx 0.693 \).
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