Discussion

Experiments show for a gas at low pressure p and constant temperature T has rate of change of volume V(p) equals to

Answer: B

Start from Boyle's law at constant temperature:

\[ V = \frac{c}{p} \]

Differentiating with respect to \( p \):

\[ \frac{dV}{dp} = -\frac{c}{p^{2}} \]

Since \( c = pV \), this becomes

\[ \frac{dV}{dp} = -\frac{pV}{p^{2}} = -\frac{V}{p} \]

The negative sign reflects that volume falls as pressure rises.

No comment is present. Be the first to comment.

Loading…