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If rate of flow of water of tank's inlet and outlet is constant so rate of change of volume w.r.t time i.e dV/dt will be

  • A.1
  • B.−1/x
  • C.∞
  • D.0

Answer: D

Volume changes at the difference between what flows in and what flows out.

\[ \frac{dV}{dt} = \text{rate in} - \text{rate out} \]

The two rates are equal and constant, so the difference is zero:

\[ \frac{dV}{dt} = 0 \]

The volume is therefore constant - the tank is in steady state, neither filling nor draining.

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