Discussion
In derivative equation, F(x,y,y', ...,yn)=0 y is function of
Answer: A
In \( F(x, y, y', \ldots, y^{(n)}) = 0 \), the variable \( x \) is independent and \( y \) is the unknown function of \( x \).
\[ y = y(x), \qquad y' = \frac{dy}{dx} \]
The primes are derivatives with respect to \( x \), which is what fixes \( x \) as the independent variable.
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