Discussion
Which equation is correct for a digital gate with symbols carrying usual meaning ?
Answer: D
The correct equation is \(V_{NH} = V_{0H(Min)} - V_{1H(Min)}\), where the paper prints 0 and 1 for the O (output) and I (input) of \(V_{OH}\) and \(V_{IH}\).
The high-level noise margin is the gap between the lowest guaranteed high output of one gate and the lowest input the next gate still reads as high. Similarly the low-level margin is \(V_{NL} = V_{IL(Max)} - V_{OL(Max)}\).
Options A and B add the levels instead of subtracting them, and option C mixes the high-level output with the low-level margin. For standard TTL, for example, \(V_{OH(Min)} = 2.4\) V and \(V_{IH(Min)} = 2.0\) V give a high noise margin of 0.4 V.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development