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Odd parity of a word can be conveniently tested by

  • A.OR gate
  • B.AND gate
  • C.NOR gate
  • D.XOR gate

Answer: D

Correct answer: XOR gate

An XOR gate outputs 1 when an odd number of its inputs are 1, which is exactly what a parity test asks. Chaining XOR gates over a word therefore gives 1 for odd parity and 0 for even. AND, OR and NOR have no such property.

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