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The power dissipation, PD, of a logic gate is the product of the ________.

  • A.dc supply voltage and the peak current
  • B.dc supply voltage and the average supply current
  • C.ac supply voltage and the peak current
  • D.ac supply voltage and the average supply current

Answer: B

Correct answer: dc supply voltage and the average supply current

Power dissipation is

\[ P_D = V_{CC}\times I_{CC(avg)} \]

The average current is used because the current drawn varies as the gate switches; the peak value would overstate the power, and the supply is dc, not ac.

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