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What can we correctly say about proposition P1:
P1 : (p v ˥q) ^ (q →r) v (r v p)

  • A.P1 is tautology
  • B.P1 is unsatisfiable
  • C.If p is true and q is false and r is false, the P1 is true
  • D.If p is false and q is true and r is false, then P1 is true

Answer: C

Correct answer: If p is true and q is false and r is false, the P1 is true

Conjunction binds more tightly than disjunction, so the formula reads \( [(p \lor \lnot q) \land (q \to r)] \lor (r \lor p) \). With p true, q false and r false: \( p \lor \lnot q \) is true, \( q \to r \) is true because the antecedent is false, so the bracket is true and the whole is true. It is not a tautology, since p false, q true and r false makes every disjunct false.

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